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Given: PQ= TQ, UQ: QSProve: PS TUReasonsStatements1. PQ= TO, UQ= OS2. PQ = TQ, UQ = QS3. PQ+ QS = PS...
4 months ago
Q:
Given: PQ= TQ, UQ: QSProve: PS TUReasonsStatements1. PQ= TO, UQ= OS2. PQ = TQ, UQ = QS3. PQ+ QS = PS; TQ + QU = TU4. TQ + QS = PS5. TQ + QS = TU6. PS = TU7. PS = TU1. Given2. reflexive Ž3. Addition Poe4. Seament Addition post5. Seament Addition Post6. U7. Definition of CongroencelGina Wilson (All Things Algebra), 2014
Accepted Solution
A:
Answer:The required prove is shown below.Step-by-step explanation:Consider the provided statement.The required figure is shown below: Statement ReasonsPQ ≅ TQ; UQ ≅ QS GivenPQ = TQ, UQ = QS Definition of CongruencePQ + QS = PS; TQ+QU = TU Segment Addition PostulateTQ + QS = PS Substitution (PQ = TQ)TQ + QS = TU Substitution (QU = QS)PS = TU Transitive PropertyProve: PS ≅TU Definition of CongruenceHence, the required prove is shown above.